2*(x^2)-(2i)x+10=0

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Solution for 2*(x^2)-(2i)x+10=0 equation:


Simplifying
2(x2) + -1(2i) * x + 10 = 0

Remove parenthesis around (2i)
2x2 + -1 * 2i * x + 10 = 0

Multiply -1 * 2
2x2 + -2i * x + 10 = 0

Multiply i * x
2x2 + -2ix + 10 = 0

Reorder the terms:
10 + -2ix + 2x2 = 0

Solving
10 + -2ix + 2x2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -2ix + -10 + 2x2 = 0 + -10

Reorder the terms:
10 + -10 + -2ix + 2x2 = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -2ix + 2x2 = 0 + -10
-2ix + 2x2 = 0 + -10

Combine like terms: 0 + -10 = -10
-2ix + 2x2 = -10

Add '-2x2' to each side of the equation.
-2ix + 2x2 + -2x2 = -10 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-2ix + 0 = -10 + -2x2
-2ix = -10 + -2x2

Divide each side by '-2x'.
i = 5x-1 + x

Simplifying
i = 5x-1 + x

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